comp.lang.idl-pvwave archive - RDF feed
type: channel
description: Messages from Usenet group comp.lang.idl-pvwave, compiled by Paulo Penteado
items: Re: Binary (0s and 1s) output

Re: Binary (0s and 1s) output
type: item
description: josegomez@gmx.net writes: > I'm very new to IDL, and I'm trying to convert 5 integers into a series > of 40 logical (0/1) values. I have done this in fortran in the past > using an internal write, and then converting each element in the output > string into a 0 or 1. Given my limited knowledge of IDL, I tried to use > print with a format specifier, as follows: > IDL> print,format='(2B8.8)',0,255 > % Unexpected text in format. > "(2B8.8)" > ^ > % Execution halted at: $MAIN$ > > According to my notes, the B format is there and can be used (this is > IDL 6.0). > > The other problem is how to convert the (potentially!) resulting test > string into an array of integers. Well, this is new to me, but it seems to work here on IDL 6.1.1 in Windows: IDL> print,format='(2B8.8)',0,255 0000000011111111 Cheers, David -- David Fanning, Ph.D. Fanning Software Consulting, Inc. Coyote's Guide to IDL Programming: http://www.dfanning.com/
creator: David Fanning
date: 2004-12-07T16:20:08-00:00

Re: Binary (0s and 1s) output
type: item
description: josegomez@gmx.net wrote: > Hi! > I'm very new to IDL, and I'm trying to convert 5 integers into a series > of 40 logical (0/1) values. I have done this in fortran in the past > using an internal write, and then converting each element in the output > string into a 0 or 1. Given my limited knowledge of IDL, I tried to use > print with a format specifier, as follows: > IDL> print,format='(2B8.8)',0,255 > % Unexpected text in format. > "(2B8.8)" > ^ > % Execution halted at: $MAIN$ > > According to my notes, the B format is there and can be used (this is > IDL 6.0). > > The other problem is how to convert the (potentially!) resulting test > string into an array of integers. > > Many thanks > I think the "B" format code was introduces in IDL 6.1. Benjamin
creator: Benjamin Hornberger
date: 2004-12-07T16:20:10-00:00

Re: Binary (0s and 1s) output
type: item
description: David Fanning writes: > Well, this is new to me, but it seems to work here > on IDL 6.1.1 in Windows: > > IDL> print,format='(2B8.8)',0,255 > 0000000011111111 Oh, right. It does cause an error in IDL 6.0. Probably wasn't ready for prime time then. :-( Cheers, David -- David Fanning, Ph.D. Fanning Software Consulting, Inc. Coyote's Guide to IDL Programming: http://www.dfanning.com/
creator: David Fanning
date: 2004-12-07T16:21:46-00:00

Re: Binary (0s and 1s) output
type: item
description: David Fanning wrote: > David Fanning writes: > >> Well, this is new to me, but it seems to work here >> on IDL 6.1.1 in Windows: >> >> IDL> print,format='(2B8.8)',0,255 >> 0000000011111111 > > Oh, right. It does cause an error in IDL 6.0. Probably > wasn't ready for prime time then. :-( Hmmmm... That's what I thought. I guess I'll need to do this in 6.1, and I can just then use the READS command to convert to an integer array. Many thanks for your help, all who replied! Jose
creator: josegomez
date: 2004-12-07T17:15:58-00:00

Re: Binary (0s and 1s) output
type: item
description: josegomez@gmx.net wrote: > Hi! > I'm very new to IDL, and I'm trying to convert 5 integers into a series > of 40 logical (0/1) values. I have done this in fortran in the past > using an internal write, and then converting each element in the output > string into a 0 or 1. Given my limited knowledge of IDL, I tried to use > print with a format specifier, as follows: > IDL> print,format='(2B8.8)',0,255 > % Unexpected text in format. > "(2B8.8)" > ^ > % Execution halted at: $MAIN$ > > According to my notes, the B format is there and can be used (this is > IDL 6.0). > > The other problem is how to convert the (potentially!) resulting test > string into an array of integers. I think this printing/reading is quite ugly. Better do something like: bytIn = [ your byte value array] nIn = n_elements( bytIn) boolOut = bytarr( 8, nIn) for bit=0,7 do begin boolOut[ bit, *] = (bytIn and 2^bit) gt 0 endfor boolOut[ bitnumber, inputIntegerNumber] contains now your result HDH, marc
creator: marc schellens[1]
date: 2004-12-08T05:57:24-00:00