comp.lang.idl-pvwave archive - RDF feed
type: channel
description: Messages from Usenet group comp.lang.idl-pvwave, compiled by Paulo Penteado
items: Re: array operations and memory consumption

Re: array operations and memory consumption
type: item
description: On Jan 4, 3:19 pm, dktr....@gmail.com wrote: > Hi all, > > Apologies in advance if this is old hat ... I've got a question > regarding IDL's memory usage that can be boiled down in the following > example: > > IDL> a = BINDGEN(100,100,100) > IDL> baseMem = (MEMORY())[0] > IDL> a = a + 1 > IDL> PRINT, (MEMORY())[3] - baseMem > 2000049 Consider using the increment operator like this: IDL> a++ This does an increment in-place with little additional memory (a few bytes). The assignment c-style operators like this one below, use double the memory. IDL> a += 1 I haven't seen MEMORY before. Is this new in 7.0? I use help,/memory which doesn't behave like I expect. Good luck, Don
creator: don.woodraska
date: 2008-01-04T23:16:06-00:00

Re: array operations and memory consumption
type: item
description: On Jan 4, 3:19 pm, dktr....@gmail.com wrote: > Hi all, > > Apologies in advance if this is old hat ... I've got a question > regarding IDL's memory usage that can be boiled down in the following > example: > > IDL> a = BINDGEN(100,100,100) > IDL> baseMem = (MEMORY())[0] > IDL> a = a + 1 > IDL> PRINT, (MEMORY())[3] - baseMem > 2000049 > > I've tried modifying "a = a + 1" with various combinations of pointers > and the TEMPORARY function, but can't reduce this temporary elevated > memory consumption. Compare the above with a call to CONGRID: > > IDL> a = BINDGEN(100,100,100) > IDL> baseMem = (MEMORY())[0] > IDL> a = CONGRID(a, 100, 100, 100) > IDL> PRINT, (MEMORY())[3] - baseMem > 1003941 > > I'm working with some very large image arrays and trying to do some > "in place" manipulations. While I can slink by with the temporary > memory usage of the latter CONGRID-type operations, addition (or > multiplication) of an array by a scalar breaks the bank. > > Any tips or directions to a helpful tutorial on IDL's memory policies > would be greatly appreciated. Thanks! Be careful with type conversion here! In particular, 1 is a short integer (or long integer depending on if compile_opt defint32 is used), so a = a + 1 here converts a to type int. Consider the following: IDL> a = bindgen(100, 100, 100) IDL> orig_mem = memory(/current) IDL> a = a + 1 IDL> print, memory(/highwater) - orig_mem 2000082 IDL> a = bindgen(100, 100, 100) IDL> orig_mem = memory(/current) IDL> a = a + 1B IDL> print, memory(/highwater) - orig_mem 1000096 IDL> a = bindgen(100, 100, 100) IDL> orig_mem = memory(/current) IDL> a = temporary(a) + 1B IDL> print, memory(/highwater) - orig_mem 91 IDL> IDL> a = bindgen(100, 100, 100) IDL> orig_mem = memory(/current) IDL> a += 1B IDL> print, memory(/highwater) - orig_mem 91 IDL> IDL> a = bindgen(100, 100, 100) IDL> orig_mem = memory(/current) IDL> a++ IDL> print, memory(/highwater) - orig_mem 91 Mike -- www.michaelgalloy.com Tech-X Corporation Software Developer II
creator: Michael Galloy
date: 2008-01-04T23:16:59-00:00

Re: array operations and memory consumption
type: item
description: Type conversion! That was what was missing from my understanding. This makes much more sense now. Thanks for the pointers. I also had forgotten the increment operator, although I was looking for something more general. -Ted On Jan 4, 3:16 pm, "mgal...@gmail.com" <mgal...@gmail.com> wrote: > On Jan 4, 3:19 pm, dktr....@gmail.com wrote: > > > >> Hi all, > >> Apologies in advance if this is old hat ... I've got a question >> regarding IDL's memory usage that can be boiled down in the following >> example: > >> IDL> a = BINDGEN(100,100,100) >> IDL> baseMem = (MEMORY())[0] >> IDL> a = a + 1 >> IDL> PRINT, (MEMORY())[3] - baseMem >> 2000049 > >> I've tried modifying "a = a + 1" with various combinations of pointers >> and the TEMPORARY function, but can't reduce this temporary elevated >> memory consumption. Compare the above with a call to CONGRID: > >> IDL> a = BINDGEN(100,100,100) >> IDL> baseMem = (MEMORY())[0] >> IDL> a = CONGRID(a, 100, 100, 100) >> IDL> PRINT, (MEMORY())[3] - baseMem >> 1003941 > >> I'm working with some very large image arrays and trying to do some >> "in place" manipulations. While I can slink by with the temporary >> memory usage of the latter CONGRID-type operations, addition (or >> multiplication) of an array by a scalar breaks the bank. > >> Any tips or directions to a helpful tutorial on IDL's memory policies >> would be greatly appreciated. Thanks! > > Be careful with type conversion here! In particular, 1 is a short > integer (or long integer depending on if compile_opt defint32 is > used), so a = a + 1 here converts a to type int. Consider the > following: > > IDL> a = bindgen(100, 100, 100) > IDL> orig_mem = memory(/current) > IDL> a = a + 1 > IDL> print, memory(/highwater) - orig_mem > 2000082 > > IDL> a = bindgen(100, 100, 100) > IDL> orig_mem = memory(/current) > IDL> a = a + 1B > IDL> print, memory(/highwater) - orig_mem > 1000096 > > IDL> a = bindgen(100, 100, 100) > IDL> orig_mem = memory(/current) > IDL> a = temporary(a) + 1B > ID…
creator: dktr.ted
date: 2008-01-04T23:55:33-00:00