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Re: FORTRAN -> IDL [message #10718 is a reply to message #2702]

Mon, 12 January 1998 00:00

Harald Frey
Messages: 41
Registered: March 1997

Member

Kelly Dean wrote:

> I am converted some FORTRAN code into IDL, but I am confused what this
> FORTRAN statment "SINE(X)=SIN(.01745329*X) " in this function is trying
> to do.
>
> FUNCTION GETDIST (HEIGHT,ANGLE,ZENANG,SLANT)
> DATA RAD/3437.748/
> SINE(X)=SIN(.01745329*X)
> ARCSIN(X)=57.29578*ASIN(X)
> ANG=ABS(ANGLE)
> FAC=SINE(ANG)/RAD
> .
> .
> .
>
> Any hints?
>
> Kelly Dean
> CSU/CIRA

!pi/180.=0.0174533

Harald Frey

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[Message index]

		Fortran -> IDL translator By: uk2 on Wed, 31 August 1994 15:50
		Re: Fortran -> IDL translator By: amaravad on Fri, 02 September 1994 09:01
		Re: FORTRAN -> IDL By: Harald Frey on Mon, 12 January 1998 00:00
		Re: FORTRAN -> IDL By: Robert S. Hill on Sun, 11 January 1998 00:00
		Re: FORTRAN -> IDL By: rivers on Sun, 11 January 1998 00:00
		Re: FORTRAN -> IDL By: Kevin Ivory on Sun, 11 January 1998 00:00

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