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Routine for converting 80x87 doubles to XDR (IEEE) format? [message #1175]

Tue, 06 July 1993 14:26

ryba
Messages: 33
Registered: October 1992

Member

I'd like to read in some data dumped from a PC that includes some
8-byte reals. BYTEORDER only does byte swaps for shorts (2 bytes) and
longs (4 bytes). If I recall, the 80x87 uses IEEE format, but with the
"little endian" format of the Intel chip. Is that correct? If so, I just
need an extended byte-order to do an 8-byte swap. If not, a canned routine
to do the conversion would be nice.

--
Dr. Marty Ryba | Generation X:
MIT Lincoln Laboratory | Too young to be cynical,
ryba@ll.mit.edu | too old to be optimistic.
Of course nothing I say here is official policy!!!!

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Routine for converting 80x87 doubles to XDR (IEEE) format?

By: ryba on Tue, 06 July 1993 14:26

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