| Re: Is this a bug? [message #13072 is a reply to message #12978] |
Thu, 01 October 1998 00:00  |
menakkis
Messages: 37
Registered: June 1998
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David Foster <foster@bial1.ucsd.edu> wrote:
<...>
> ((*p).s.a)[2] = ((*p).s.a)[2] * 4
> % Temporary variables are still checked out - cleaning up...
>
> print, ((*p).s.a)[2]
> 48 ; Value was not adjusted
I think something like this came up in the newsgroup a while back, and the
problem was that the brackets on the LHS effectively turned it into a RHS,
with the REAL LHS becoming a temporary variable.
mmm. I didn't do too well there. How about... You want ((*p).s.a)[2] to
receive a value. But IDL sees those outer brackets and decides: "I've got
to calculate something here; I'll stick the result in a temporary variable,
like I usually do." So you get a temporary variable containing (*p).s.a (or
maybe even ((*p).s or *p ???). Finally, IDL assigns your (actual) RHS result
to element 2 of the "a" member of this temporary variable, and then chucks
away the temporary variable because, as far as it's concerned, the temporary
variable has nowhere to go.
Perhaps like me you're a bit uneasy about having to put brackets around
dereferenced pointers to get at structure members or array elements therein.
It really does go against the grain, doesn't it? Any superfluous brackets
and you get this "calculation mode" thing kicking in. I must say that I
can't see a way around this, though, given what I gather about how IDL's
variables work. I guess an interpretation of what (*p) means is: "make a
temporary variable *control* structure to get at the contents of p"; you can
then use the "thing" (*p) as if it was a variable name. It takes some
getting used-to, but it *is* very efficient for dereferencing just an array
element or structure member. (I was going to sound forth on how I dislike
this syntax but had second thoughts.)
Peter Mason
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