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Float procedure [message #13751]

Tue, 01 December 1998 00:00

Charlie Solomon
Messages: 10
Registered: September 1998

Junior Member

Hi,

Can anyone shed some light on how this byte array is converted into a
floating point number?
two_words = bytarr(4)
two_words = [244, 232, 165, 64]
IDL> print, two_words, format = '(z)'
f4
e8
a5
40
IDL> print, float(two_words, 0)
2.13062e-038

On my computer at work (NT4, x86) I get a different value...5.18469
Here at home (Win98, x86) I get this really small number....
IDL> print, !version
{ x86 Win32 Windows 5.1.1 Jul 20 1998}

Thanks in advance,

Charlie Solomon
Raytheon Systems Co.
El Segundo, CA

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