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Re: Faster than this...
| Re: Faster than this... [message #18679] |
Thu, 03 February 2000 00:00 |
Craig Markwardt
Messages: 1869
Registered: November 1996
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Senior Member |
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Ricardo Fonseca <zamb@physics.ucla.edu> writes:
>
> I have this line of code in IDL 5.2a
>
> for j=0, N-1 do Data[j]=XAxisData[j]^2*Data[j]
>
> Where both Data and XAxisData have the same dimension N.
> Does anyone know if there is a faster way of doing this
> (i.e. avoiding the for cicle) ?
I hope this isn't a trick question. The expression
Data = XAxisDAta^2 * Data
should work fine. Don't worry about Data being overwritten. The
right hand side is fully evaluated with the "old" value of Data,
before the "new" value of Data is assigned.
Craig
--
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Craig B. Markwardt, Ph.D. EMAIL: craigmnet@cow.physics.wisc.edu
Astrophysics, IDL, Finance, Derivatives | Remove "net" for better response
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