pie-shaped polar plot in IDL? [message #28031] |
Fri, 16 November 2001 14:57  |
lisakewley
Messages: 1 Registered: November 2001
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Junior Member |
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Greetings,
I am trying to create a pie-shaped polar plot (not a pie-chart),
such as in this figure:
http://tdc-www.harvard.edu/uzc/f6a.gif
I have searched this newsgroup and found a few scripts people have
written, but they generally create plots in 360 degrees. I need the
curved axis to subtend an angle of ~130 degrees, but need to also be
able to define/spread my own data range (eg 8hours to 18 hours) over
the curved axis. I hope this makes sense.
Has anyone done this, or know of a way of doing it in IDL? I'm not
that familiar with doing much other than the stock-standard IDL
plotting or
mapping routines.
Thanks,
Lisa
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Re: pie-shaped polar plot in IDL? [message #28118 is a reply to message #28031] |
Mon, 19 November 2001 06:44  |
Relayer
Messages: 1 Registered: November 2001
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Junior Member |
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"Lisa Kewley" <lisakewley@hotmail.com> wrote in message
news:1b37dc5.0111161457.2e7c5fd@posting.google.com...
> Greetings,
>
> I am trying to create a pie-shaped polar plot (not a pie-chart),
> such as in this figure:
>
> http://tdc-www.harvard.edu/uzc/f6a.gif
>
> I have searched this newsgroup and found a few scripts people have
> written, but they generally create plots in 360 degrees. I need the
> curved axis to subtend an angle of ~130 degrees, but need to also be
> able to define/spread my own data range (eg 8hours to 18 hours) over
> the curved axis. I hope this makes sense.
>
> Has anyone done this, or know of a way of doing it in IDL? I'm not
> that familiar with doing much other than the stock-standard IDL
> plotting or
> mapping routines.
>
> Thanks,
> Lisa
Hi Lisa,
I have had a similar problem in the past, and never did get a satisfactory
result. If you get a reply on this could you please forward it to me at
relayer@dreamtheater.zzn.com
Thank you,
R.
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