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Re: extract subarray dynamically? [message #31597]

Thu, 01 August 2002 07:14

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

David Fanning (david@dfanning.com) writes:

> temp = arrary[start_x, (start_x + s[0]) < (ss[0]-1]), $
> start_y, (start_y + s[1]) < (ss[1]-1]) ]

Damn. I *always* do that. :-(

Should be, of course:

temp = arrary[start_x:(start_x + s[0]) < (ss[0]-1]), $
start_y:(start_y + s[1]) < (ss[1]-1]) ]

Cheers,

David
--
David W. Fanning, Ph.D.
Fanning Software Consulting, Inc.
Phone: 970-221-0438, E-mail: david@dfanning.com
Coyote's Guide to IDL Programming: http://www.dfanning.com/
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		Re: extract subarray dynamically? By: David Fanning on Thu, 01 August 2002 07:14
		Re: extract subarray dynamically? By: David Fanning on Thu, 01 August 2002 07:12

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