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Re: integer? [message #31628 is a reply to message #31622]

Tue, 30 July 2002 08:34

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

tom (tom2959@21cn.com) writes:

> This is a segment of HEX: 00 00 00 64
>
> there are two 2byte-integers in it.
> But when I set
> a=0
> readu,lun,a ; I hope a=hex(00 00)
> print,a
> the result is 100. That's a=hex(00 00 00 64)
> that's the same as "a=0l readu,lun,a"
>
> how to read 2byte integer then?

Like this:

IDL> a = '00000064'x
IDL> HELP, a
A INT = 100
IDL> Print, 'High order byte: ', Byte(a, 1)
High order byte: 0
IDL> Print, 'Low order byte: ', Byte(a, 0)
Low order byte: 100

Cheers,

David
--
David W. Fanning, Ph.D.
Fanning Software Consulting, Inc.
Phone: 970-221-0438, E-mail: david@dfanning.com
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Toll-Free IDL Book Orders: 1-888-461-0155

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[Message index]

		Re: integer? By: Nigel Wade on Fri, 02 August 2002 02:01
		Re: integer? By: tom on Thu, 01 August 2002 18:07
		Re: integer? By: David Fanning on Wed, 31 July 2002 06:56
		Re: integer? By: Nigel Wade on Wed, 31 July 2002 06:25
		Re: integer? By: tom on Wed, 31 July 2002 05:26
		Re: integer? By: Nigel Wade on Wed, 31 July 2002 01:32
		Re: integer? By: David Fanning on Tue, 30 July 2002 08:34

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