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Re: Hough transform help [message #31805] Mon, 19 August 2002 10:01
Chris Torrence is currently offline  Chris Torrence
Messages: 5
Registered: March 2001
Junior Member
Hi Marshall,

Have you tried setting the XMIN and YMIN keywords? HOUGH and RADON assume
that the center of your transform is the center of the image (e.g. at pixel
[127,127] in your case). It then returns theta values in the range 0 to
+180. Positive rho values are above the X axis (at say X=127), while
negative rho values are below the X axis.

Setting XMIN=0 and YMIN=0 will shift the transform origin down to the lower
left corner of your image. Note that you will still get both + and - rho
values, but the negative rho values will all have theta > 90, which
indicates "rays" going from the lower-left to upper-right. This are probably
useless for you, and can be removed by using RMIN=0 and the NRHO keyword.

The easiest way to visualize this is to look at the diagram in the docs
(which I won't attempt to reproduce here), and imagine swinging that tangent
line around the origin, and "shooting" rays thru your image.

Hope this helps.

-Chris


"Marshall Perrin" <mperrin+news@arkham.berkeley.edu> wrote in message
news:ajkipq$b33$1@agate.berkeley.edu...
> I have a 256x256 floating-point image. I am doing this:
> edge_enh = sobel(image)
> h = hough(edge_enh,/gray,rho=rho,theta=theta)
>
> and it very nicely detects the lines in the image as bright
> points in the Hough transform. However, I want to extract the slopes
> and intercepts of those lines (in standard y=mx+b format). Well, that
> should be easy given rho and theta for each line - except that
> the rho which is being returned ranges from -181 to 181.
> Negative values don't make any sense to me, particularly given
> that my image looks something like
> +-----------+
> | \ | |
> | \ | |
> | \ \ | |
> | \ \ | |
> +-----------+
> ..all of which are clearly to the right of the origin and thus should
> have positive rho. It's getting the thetas perfectly correct as far
> as I can tell.
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