| IDL & Memory Usage... [message #31920] |
Tue, 03 September 2002 06:47  |
Randall Skelton
Messages: 169
Registered: October 2000
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Senior Member |
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Hi all,
Does anyone know how IDL 5.5a breaks up into smaller processes under
Linux? When I run top on my machine I see:
------------------------------------------------------------ -------------------
2:37pm up 12 days, 4:41, 10 users, load average: 0.16, 0.12, 0.09
85 processes: 84 sleeping, 1 running, 0 zombie, 0 stopped
CPU0 states: 0.0% user, 2.2% system, 0.0% nice, 97.2% idle
CPU1 states: 0.0% user, 0.0% system, 0.0% nice, 100.0% idle
Mem: 3089264K av, 2238680K used, 850584K free, 196K shrd, 200332K buff
Swap: 6289320K av, 49024K used, 6240296K free 939340K cached
PID USER PRI NI SIZE RSS SHARE STAT %CPU %MEM TIME COMMAND
579 rhs 8 0 828M 828M 3912 S 0.0 27.4 74:11 idl
583 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
584 rhs 9 0 828M 828M 3912 S 0.0 27.4 15:46 idl
585 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
------------------------------------------------------------ -------------------
I only have one IDL session running, but 4 separate processes appear. It
also appears that each is consuming 828MB of RAM. Is this an attempt to
get around the 2.1GB address limit for 32-bit machines? I'll admit this
is a relatively large calculation but IDL cannot *REALLY* be taking 110%
of my memory resources ;)
Cheers,
Randall
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| Re: IDL & Memory Usage... [message #32007 is a reply to message #31920] |
Wed, 04 September 2002 03:44  |
Nigel Wade
Messages: 286
Registered: March 1998
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Senior Member |
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Randall Skelton wrote:
> Hi all,
>
> Does anyone know how IDL 5.5a breaks up into smaller processes under
> Linux? When I run top on my machine I see:
>
>
------------------------------------------------------------ -------------------
> 2:37pm up 12 days, 4:41, 10 users, load average: 0.16, 0.12, 0.09
> 85 processes: 84 sleeping, 1 running, 0 zombie, 0 stopped
> CPU0 states: 0.0% user, 2.2% system, 0.0% nice, 97.2% idle
> CPU1 states: 0.0% user, 0.0% system, 0.0% nice, 100.0% idle
> Mem: 3089264K av, 2238680K used, 850584K free, 196K shrd, 200332K
> buff
> Swap: 6289320K av, 49024K used, 6240296K free 939340K
> cached
>
> PID USER PRI NI SIZE RSS SHARE STAT %CPU %MEM TIME COMMAND
> 579 rhs 8 0 828M 828M 3912 S 0.0 27.4 74:11 idl
> 583 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
> 584 rhs 9 0 828M 828M 3912 S 0.0 27.4 15:46 idl
> 585 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
>
------------------------------------------------------------ -------------------
>
> I only have one IDL session running, but 4 separate processes appear. It
> also appears that each is consuming 828MB of RAM. Is this an attempt to
> get around the 2.1GB address limit for 32-bit machines? I'll admit this
> is a relatively large calculation but IDL cannot *REALLY* be taking 110%
> of my memory resources ;)
>
> Cheers,
> Randall
I would assume that they are threads rather than real processes.
The way Linux implements threads is rather strange, they are basically
individual processes which share a lot of kernel resources and have the
same VM (at least I *think* that's the way it's done).
--
Nigel Wade, System Administrator, Space Plasma Physics Group,
University of Leicester, Leicester, LE1 7RH, UK
E-mail : nmw@ion.le.ac.uk
Phone : +44 (0)116 2523568, Fax : +44 (0)116 2523555
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| Re: IDL & Memory Usage... [message #32008 is a reply to message #31920] |
Wed, 04 September 2002 00:56 |
Timm Weitkamp
Messages: 66
Registered: August 2002
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Member |
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On 03.09.02 at 09:48 -0500, Craig Markwardt wrote:
> I will submit that idl "fork()s" itself for each widget that appears or
> perhaps creates a new thread, which is the same as a new process under
> Linux. This is a common approach for X-windows applications.
I have noticed the same behavior as Randall without running any widgets,
and my guess was that it is due to 5.5's multithreading.
Timm
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| Re: IDL & Memory Usage... [message #32018 is a reply to message #31920] |
Tue, 03 September 2002 07:48 |
Craig Markwardt
Messages: 1869
Registered: November 1996
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Senior Member |
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Randall Skelton <rhskelto@atm.ox.ac.uk> writes:
> Hi all,
>
> Does anyone know how IDL 5.5a breaks up into smaller processes under
> Linux? When I run top on my machine I see:
>
> ------------------------------------------------------------ -------------------
> 2:37pm up 12 days, 4:41, 10 users, load average: 0.16, 0.12, 0.09
> 85 processes: 84 sleeping, 1 running, 0 zombie, 0 stopped
> CPU0 states: 0.0% user, 2.2% system, 0.0% nice, 97.2% idle
> CPU1 states: 0.0% user, 0.0% system, 0.0% nice, 100.0% idle
> Mem: 3089264K av, 2238680K used, 850584K free, 196K shrd, 200332K buff
> Swap: 6289320K av, 49024K used, 6240296K free 939340K cached
>
> PID USER PRI NI SIZE RSS SHARE STAT %CPU %MEM TIME COMMAND
> 579 rhs 8 0 828M 828M 3912 S 0.0 27.4 74:11 idl
> 583 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
> 584 rhs 9 0 828M 828M 3912 S 0.0 27.4 15:46 idl
> 585 rhs 9 0 828M 828M 3912 S 0.0 27.4 0:00 idl
> ------------------------------------------------------------ -------------------
Hi Randall--
Let me guess. Are you running three or four widget programs? If the
answer is yes, I will submit that idl "fork()s" itself for each widget
that appears or perhaps creates a new thread, which is the same as a
new process under Linux. This is a common approach for X-windows
applications.
The second point is that all of these processes share the same memory,
so they aren't using 4 x the memory of a single one.
Hope that helps, [ and is right! ]
Craig
--
------------------------------------------------------------ --------------
Craig B. Markwardt, Ph.D. EMAIL: craigmnet@cow.physics.wisc.edu
Astrophysics, IDL, Finance, Derivatives | Remove "net" for better response
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