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Re: 3D-coordinates of index returned MAX() [message #34681 is a reply to message #34667]

Mon, 07 April 2003 13:32

Mark Hadfield
Messages: 783
Registered: May 1995

Senior Member

"Marc Schellens" <m_schellens@hotmail.com> wrote in message
news:3E916642.1070904@hotmail.com...
> I wote something similar to Mark, but here you convert all
> indices at once.

Great, I'll steal that idea.

> And instead of a list of dimensions, you just
> call it with the array which was indexed by the 'where' function.

Yeah, I thought about that, but I figured there *might* be a situation where
one wants to calculated n-dimensional indices without having (or wanting to
create) an array with that dimensionality. ... I haven't actually
encountered this situation however.

--

Mark Hadfield "Ka puwaha te tai nei, Hoea tatou"
m.hadfield@niwa.co.nz
National Institute for Water and Atmospheric Research (NIWA)

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[Message index]

		Re: 3D-coordinates of index returned MAX() By: Alexander Gro� on Tue, 08 April 2003 09:40
		Re: 3D-coordinates of index returned MAX() By: Mark Hadfield on Mon, 07 April 2003 13:32
		Re: 3D-coordinates of index returned MAX() By: marc schellens[1] on Mon, 07 April 2003 04:51
		Re: 3D-coordinates of index returned MAX() By: Mark Hadfield on Sun, 06 April 2003 13:28
		Re: 3D-coordinates of index returned MAX() By: David Fanning on Sun, 06 April 2003 13:03

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