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Re: is this a bug in IDL? [message #37377 is a reply to message #37376]

Tue, 16 December 2003 03:09

Ben Panter
Messages: 102
Registered: July 2003

Senior Member

Aramis Martinez wrote:
> k=0
> for i=0,8759 do begin
> x=vbs(2,i)
> if x gt 0.0 then k=k+1 & x=0 & vbs(2,i)=x
> endfor
> print, k
>
> k=0
> for i=0,8759 do begin
> x=vbs(2,i)
> ;; version A
> if x gt 0.0 then x=0 & k=k+1 & vbs(2,i)=x
> ;; version B
> if x gt 0.0 then k=k+1 & x=0 & vbs(2,i)=x
> endfor
> print, k
>

I'm no expert, but I think that possibly your code is using & in the
wrong way - as far as I understand it (correct me if I'm wrong guys!!) &
means "complete the previous command then do the thing after me" - so
your code actually reads:

k=0
for i=0,8759 do begin
x=vbs(2,i)
if x gt 0.0 then x=0
k=k+1
vbs(2,i)=x
endfor

or

k=0
for i=0,8759 do begin
x=vbs(2,i)
if x gt 0.0 then k=k+1
x=0
vbs(2,i)=x
endfor

To get the behaviour that you want I think you need another begin...end set:

k=0
for i=0,8759 do begin
x=vbs(2,i)
if x gt 0.0 then begin
k=k+1
x=0
vbs(2,i)=x
end
endfor

--
Ben Panter, Edinburgh
My name (no spaces)@bigfoot which is a com.

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[Message index]

		Re: is this a bug in IDL? By: Wonko[3] on Tue, 16 December 2003 02:58
		Re: is this a bug in IDL? By: Ben Panter on Tue, 16 December 2003 03:09
		Re: is this a bug in IDL? By: aramisgm on Tue, 16 December 2003 13:17

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