| Re: "Color vectors" & shading [message #37741] |
Wed, 21 January 2004 10:41 |
Karl Schultz
Messages: 341
Registered: October 1999
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Senior Member |
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"Neil" <nasalmon@onetel.net.uk> wrote in message
news:74039481.0401210024.11f5b707@posting.google.com...
> "Karl Schultz" <kschultz_no_spam@rsinc.com> wrote in message
news:<100rj8ksoii7b80@corp.supernews.com>...
>> "Neil" <nasalmon@onetel.net.uk> wrote in message
>> news:74039481.0401201339.d26efa4@posting.google.com...
>>> Does anyone know how i correctly implement "color vectors" in
>>> "setProperty" to give each polygon of an object its own predetermined
>>> intensity level or colour? It should be that setting "shading" = 0 in
>>> "setProperty" should make it so that the colour of each polygon is
>>> defined by the "colour vertex" of the first vertex of the polygon
>>> connectivity. However, generally the number of "first vertices" of a
>>> polygon of an object is actually less than the number of polygons.
>>> That means you cant use this method to give each polygon of an object
>>> a predetermined different colour - or have i missed something? It
>>> seems to me that what is really needed is a colour vector for the
>>> polygons not the vertices.
>>
>> There's no way to do this today if you have vertices that are shared
between
>> polygons. There isn't a polygon color vector.
>>
>> What you could do is make a vertex list and a connectivity list that
creates
>> a set of independent polygons and then set the color of all the vertices
>> belonging to each polygon to the same color. Actually, you would only
need
>> to set the first vertex of a polygon to an actual color; the rest are
>> ignored if you are doing flat shading.
>>
>> Obviously, if you have many polygons that used to share vertices, this
will
>> require more space.
>>
>> For example, if you have 4 vertices, A, B, C, D, that form 2 triangles
with
>> a shared edge, the triangles might be ABC, and DCB. If the vertices are
in
>> the vertex list as ABCD, the conn list would be 3 0 1 2 3 3 2 1. To
make
>> them independent triangles, your vertex list would be ABCDCB and the
conn
>> list 3 0 1 2 3 3 4 5. You would set the color of vert A (at 0) to the
>> desired color and the color of vert D (at 3) to the desired color. The
rest
>> of the vertex colors list can be left uninitialized.
>>
>> It isn't very efficient, but would work well if you don't have that many
>> polygons.
>>
>> Karl
>
> Karl,
>
> many thanks for your response.
>
> It's a shame there are no polygon colour vectors. If you think about
> nature and surfaces, it is the surface that has the colour. The vertex
> is just a manmade mathematical entity to descibe the surfaces. I am
> sure it would be the wish of graphics programmes to mimic nature as
> cloesly as possible in the most efficient way.
I suppose. But objects can vary in color across the extents of a single
polygon. It would be cool to be able to specify the color of every pixel on
an object, but that is what texture mapping is all about. So, the next best
thing is to specify the color at each vertex and allow interpolation between
vertices. This is a pretty effective way of handling lighting models. I
guess this is all pretty debatable.
> Is the absence of polygon colour vectors a fundamental limitation of
> IDL?
Yes. It is just a limitation of the IDLgrPolygon object.
> Does OpenGL have this limitation?
No. OpenGL has the concept of "current color" as IDL passes each vertex to
it. IDL would simply set the color of the first vertex before sending the
first vertex to OpenGL, and then not change the color for subsequent
vertices. IDL would just have to fetch the color from the polygon color
list instead of the vertex color list.
> Would there be any plans for
> RSI to introduce an efficient method in IDL to enable each polygon to
> have a predetermined and unique colour/intensity?
I can write a feature request.
The same sort of argument also applies to normals. If you are doing smooth
shading, IDL uses the vertex normals you pass or computes them, based on the
average geometric normal of polygons that use each vertex. If you are doing
flat shading, IDL computes the geometric normal of each polygon and uses
that. So, there is no way to pass in polygon normals directly. You'd have
to do the same expansion trick we have discussed for the polygon colors and
make all the vertex normals the same as the polygon normal you'd like to
have for the polygon.
> I can certainly create an artificial polygon_connectivity for
> unconnected polygons allows each polygon to have a different
> intensity.
Yes, this should work just fine, except for the efficiency issue already
discussed.
Karl
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| Re: "Color vectors" & shading [message #37746 is a reply to message #37741] |
Wed, 21 January 2004 08:45  |
David.Chevrier
Messages: 14
Registered: May 2003
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Junior Member |
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Hi,
I'm not sure if this will help or not, but I had a similar (less
complex) problem. I had three arrays: long/lat/depth and wanted to
create one semi-transparent polygon that was green for all points
above 0 (land) and blue for all points less than 0 (water). This
created a bathymetric map. Here is how I did it. I know its only two
colors and uses a lot of memory (my arrays had more than 9000 numbers
each.) (I also used the 'temporary' command a lot to get rid of
unneeded variables, but have taken most of them out here to make it
easier to read.)
MESH_OBJ,0,verts,conn,TRANSPOSE([[contourlng],[contourlat],[ contourdepth]])
verts=MESH_SMOOTH(TEMPORARY(verts), conn, /FIXED_EDGE_VERTICES)
depsize=(SIZE(verts))[2]
mapimage=REPLICATE(255b,4,3,depsize)
mapimage[3,*,*]=105b ;transparent level
oContourImage=OBJ_NEW('IDLgrImage', mapimage, BLEND_FUNCTION=[3,4],
INTERLEAVE=0, /NO_COPY)
r=MAKE_ARRAY(256,/BYTE,VALUE=0b)
g=MAKE_ARRAY(256,/BYTE,VALUE=0b)
b=MAKE_ARRAY(256,/BYTE,VALUE=255b)
depths=REFORM(verts[2,*])
lands=WHERE(depths GE 0.0, anyland)
depths=BYTSCL(TEMPORARY(depths))
IF (anyland GT 0L) THEN BEGIN
depths[TEMPORARY(lands)]=255b
g[255]=255b
b[255]=0b
ENDIF
oPalette1=OBJ_NEW('IDLgrPalette',r,g,b)
oWaterMap=OBJ_NEW('IDLgrPolygon',verts, POLYGONS=conn, $
SHADING=1, TEXTURE_MAP=oContourImage, /TEXTURE_INTERP,
HIDDEN_LINES=1, $
XCOORD_CONV=(*stateptr).xs, VERT_COLORS=depths, PALETTE=oPalette1, $
YCOORD_CONV=(*stateptr).ys, ZCOORD_CONV=(*stateptr).zs)
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| Re: "Color vectors" & shading [message #37754 is a reply to message #37746] |
Wed, 21 January 2004 00:24 |
nasalmon
Messages: 33
Registered: August 2003
|
Member |
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"Karl Schultz" <kschultz_no_spam@rsinc.com> wrote in message news:<100rj8ksoii7b80@corp.supernews.com>...
> "Neil" <nasalmon@onetel.net.uk> wrote in message
> news:74039481.0401201339.d26efa4@posting.google.com...
>> Does anyone know how i correctly implement "color vectors" in
>> "setProperty" to give each polygon of an object its own predetermined
>> intensity level or colour? It should be that setting "shading" = 0 in
>> "setProperty" should make it so that the colour of each polygon is
>> defined by the "colour vertex" of the first vertex of the polygon
>> connectivity. However, generally the number of "first vertices" of a
>> polygon of an object is actually less than the number of polygons.
>> That means you cant use this method to give each polygon of an object
>> a predetermined different colour - or have i missed something? It
>> seems to me that what is really needed is a colour vector for the
>> polygons not the vertices.
>
> There's no way to do this today if you have vertices that are shared between
> polygons. There isn't a polygon color vector.
>
> What you could do is make a vertex list and a connectivity list that creates
> a set of independent polygons and then set the color of all the vertices
> belonging to each polygon to the same color. Actually, you would only need
> to set the first vertex of a polygon to an actual color; the rest are
> ignored if you are doing flat shading.
>
> Obviously, if you have many polygons that used to share vertices, this will
> require more space.
>
> For example, if you have 4 vertices, A, B, C, D, that form 2 triangles with
> a shared edge, the triangles might be ABC, and DCB. If the vertices are in
> the vertex list as ABCD, the conn list would be 3 0 1 2 3 3 2 1. To make
> them independent triangles, your vertex list would be ABCDCB and the conn
> list 3 0 1 2 3 3 4 5. You would set the color of vert A (at 0) to the
> desired color and the color of vert D (at 3) to the desired color. The rest
> of the vertex colors list can be left uninitialized.
>
> It isn't very efficient, but would work well if you don't have that many
> polygons.
>
> Karl
Karl,
many thanks for your response.
It's a shame there are no polygon colour vectors. If you think about
nature and surfaces, it is the surface that has the colour. The vertex
is just a manmade mathematical entity to descibe the surfaces. I am
sure it would be the wish of graphics programmes to mimic nature as
cloesly as possible in the most efficient way.
Is the absence of polygon colour vectors a fundamental limitation of
IDL? Does OpenGL have this limitation? Would there be any plans for
RSI to introduce an efficient method in IDL to enable each polygon to
have a predetermined and unique colour/intensity?
I can certainly create an artificial polygon_connectivity for
unconnected polygons allows each polygon to have a different
intensity.
best regards, Neil
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| Re: "Color vectors" & shading [message #37755 is a reply to message #37754] |
Tue, 20 January 2004 16:54 |
Karl Schultz
Messages: 341
Registered: October 1999
|
Senior Member |
|
|
"Neil" <nasalmon@onetel.net.uk> wrote in message
news:74039481.0401201339.d26efa4@posting.google.com...
> Does anyone know how i correctly implement "color vectors" in
> "setProperty" to give each polygon of an object its own predetermined
> intensity level or colour? It should be that setting "shading" = 0 in
> "setProperty" should make it so that the colour of each polygon is
> defined by the "colour vertex" of the first vertex of the polygon
> connectivity. However, generally the number of "first vertices" of a
> polygon of an object is actually less than the number of polygons.
> That means you cant use this method to give each polygon of an object
> a predetermined different colour - or have i missed something? It
> seems to me that what is really needed is a colour vector for the
> polygons not the vertices.
There's no way to do this today if you have vertices that are shared between
polygons. There isn't a polygon color vector.
What you could do is make a vertex list and a connectivity list that creates
a set of independent polygons and then set the color of all the vertices
belonging to each polygon to the same color. Actually, you would only need
to set the first vertex of a polygon to an actual color; the rest are
ignored if you are doing flat shading.
Obviously, if you have many polygons that used to share vertices, this will
require more space.
For example, if you have 4 vertices, A, B, C, D, that form 2 triangles with
a shared edge, the triangles might be ABC, and DCB. If the vertices are in
the vertex list as ABCD, the conn list would be 3 0 1 2 3 3 2 1. To make
them independent triangles, your vertex list would be ABCDCB and the conn
list 3 0 1 2 3 3 4 5. You would set the color of vert A (at 0) to the
desired color and the color of vert D (at 3) to the desired color. The rest
of the vertex colors list can be left uninitialized.
It isn't very efficient, but would work well if you don't have that many
polygons.
Karl
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