| Re: Yeeeeeeeeeeeeeeeeeeeeees! [message #37878] |
Tue, 03 February 2004 07:02 |
Nuno Oliveira
Messages: 75
Registered: October 2003
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Member |
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It worked!!! I haven't done many tests but for now it seems it works.
I'm afraid that in a few days I discover that it gives me a problem
somewhere else. I hope not, and for now I have a lot of work in front of me
trying to make my tool.
Gracias, :),
Nuno.
"Nuno Oliveira" <nmoliveira@fc.ul.pt> wrote in message
news:bvnvup$1ca3$1@pegasus.fccn.pt...
> Thanks, Bruce. I was looking in the tutorials and it was not clear the
> working procedure of the where function (it is now?). It works on a mask
> right? So if have result = where(xy) it would mean that xy is a matrix (in
> the case 2-D) where de elements of the roi have value 1 and the others
have
> value 0.
>
> So maybe the solution is seeking for i,j such that xy(i,j) eq 1. If true
> then adding these (i,j) to a pointer and returning this two-dimensional
> array? What do you say? I'm going to try.
>
>
>
> Cheers,
>
>
>
> Nuno.
>
>
>
> "Bruce Bowler" <bbowler@bigelow.org> wrote in message
> news:pan.2004.02.02.17.47.37.709701@bigelow.org...
>> On Mon, 02 Feb 2004 16:40:14 +0000, Nuno Oliveira put fingers to
keyboard
>> and said:
>>
>> Based on the fact that xy is the result of a "where", I'd assume that
the
>> single number returned is the "1 dimensional index that would result if
>> the 2 dimensional array were addressed at X,Y".
>>
>> --
>>
+-------------------+--------------------------------------- ------------+
>> Bruce Bowler | To be great is to be misunderstood. - Ralph Waldo
>> 1.207.633.9600 | Emerson
>> bbowler@bigelow.org |
>>
+-------------------+--------------------------------------- ------------+
>>
>
>
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