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JULDAY-CALDAT problem [message #38267] Thu, 26 February 2004 05:40 Go to previous message
lucianor is currently offline  lucianor
Messages: 12
Registered: June 2002
Junior Member
Hi, maybe somebody has a clue about the following:

IDL> aa=JulDay(11,18,1990,2,0,0)
IDL> Caldat,aa,m,d,y,h,mi,s
IDL> print,m,d,y,h,mi,s
11 18 1990 2 0 5.3644181e-005

Why does s=5.3644181e-005 and not s=0 as it should be?

Thanks (I'm using IDL 6.0, Win XP)

Luciano.
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