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Re: Combinatorial [message #40720 is a reply to message #40719]

Tue, 31 August 2004 06:02

andrade_bahia
Messages: 5
Registered: August 2004

Junior Member

Dear Bowman
I obtained to make the combinations without needing to use recursive form.
Thanks in advance for your help.
;*********************************************************** *************
FUNCTION Combination,n,k
c=lindgen(k)
cmax=N-reverse(lindgen(k))-1
i=k-1
comb=c
while i GE 0 do begin
c[i]=c[i]+1
if c[i] GT cmax[i] then begin
i=max(where(c lt cmax))
if i eq -1 then break
c[i]=c[i]+1
for j=i+1, k-1 do c[j]=c[j-1]+1
i=k-1
endif
comb= [[comb],[c]]
;stop
endwhile
return, com
END
Adilson

Kenneth Bowman <k-bowman@null.tamu.edu> wrote in message news:<k-bowman-A330BB.12580030082004@news.tamu.edu>...
> In article <e8ecd642.0408300658.5304ce28@posting.google.com>,
> andrade_bahia@yahoo.com.br (Adilson) wrote:
>
>> Dear Bowman,
>> I Would like to thank the orientation.
>> But if the combination will be of more attributes, or either, 4x4,
>> 5x5?? How I could make?
>> Thanks in advance for your help.
>>
>> Adilson Andrade
>
> Same idea. To choose m items, you will need to nest m FOR loops. I'm
> sure other algorithms could be devised that have only a single loop.
>
> Ken Bowman

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[Message index]

		Re: Combinatorial By: andrade_bahia on Tue, 31 August 2004 06:04
		Re: Combinatorial By: andrade_bahia on Tue, 31 August 2004 06:02
		Re: Combinatorial By: K. Bowman on Mon, 30 August 2004 10:58
		Re: Combinatorial By: andrade_bahia on Mon, 30 August 2004 07:58
		Re: Combinatorial By: David Fanning on Fri, 27 August 2004 07:16
		Re: Combinatorial By: Paul Van Delst[1] on Fri, 27 August 2004 07:12
		Re: Combinatorial By: Paul Van Delst[1] on Fri, 27 August 2004 07:11
		Re: Combinatorial By: K. Bowman on Fri, 27 August 2004 06:51

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