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Re: Arrays with NaN values [message #41272 is a reply to message #41266]

Sun, 03 October 2004 22:22

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

Julio writes:

> Ok, David, but I'm using this code to put zeros in the place of Nan
>
> Image=(0*(where(float(finite Image[*,*],/Nan)))) + $
> Image*(where(NOT float(finite *Image[*,*],/Nan))))
>
> I guess I'm not using "where" function correctly, once it doesn't
> work.

Humm. Well that code looks a little strange. :-)

I think I would try something like this:

index = Where(Finite(image) EQ 0, count)
IF count NE 0 THEN image[index] = 0

Cheers,

David

--
David W. Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http:/www.dfanning.com/
Phone: 970-221-0438, IDL Book Orders: 1-888-461-0155

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[Message index]

		Re: Arrays with NaN values By: Mark Hadfield on Mon, 04 October 2004 16:58
		Re: Arrays with NaN values By: David Fanning on Mon, 04 October 2004 13:35
		Re: Arrays with NaN values By: julio on Mon, 04 October 2004 10:08
		Re: Arrays with NaN values By: David Fanning on Sun, 03 October 2004 22:22
		Re: Arrays with NaN values By: julio on Sun, 03 October 2004 13:36
		Re: Arrays with NaN values By: David Fanning on Sat, 02 October 2004 23:30
		Re: Arrays with NaN values By: Paul Van Delst[1] on Tue, 05 October 2004 09:13

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