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precedence question [message #43003]

Mon, 14 March 2005 10:35

Foldy Lajos
Messages: 268
Registered: October 2001

Senior Member

Hi guys,

I am a little bit lost in operator precedence. I think that . and [] has
the same precedence, and associate from left to right. So I expect the
following three expressions to be equivalent:

a=replicate({l:lindgen(2,3)}, 4,5)

help, a[3:6] .l [*,0:1] ; a
help, (a[3:6]).l [*,0:1] ; b
help, ((a[3:6]).l)[*,0:1] ; c

a is the same as b, but c differs. Where am I wrong?

regards,
lajos

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[Message index]

		precedence question By: Foldy Lajos on Mon, 14 March 2005 10:35
		Re: precedence question By: David Fanning on Tue, 15 March 2005 06:42
		Re: precedence question By: Foldy Lajos on Tue, 15 March 2005 06:35
		Re: precedence question By: David Fanning on Tue, 15 March 2005 06:13
		Re: precedence question By: Foldy Lajos on Tue, 15 March 2005 05:55
		Re: precedence question By: JD Smith on Fri, 18 March 2005 15:45
		Re: precedence question By: marc schellens[1] on Tue, 15 March 2005 04:43
		Re: precedence question By: Foldy Lajos on Tue, 15 March 2005 01:42
		Re: precedence question By: marc schellens[1] on Mon, 14 March 2005 23:53

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