| Re: Convert hex string to number [message #44341] |
Fri, 03 June 2005 13:43  |
Michael Wallace
Messages: 409
Registered: December 2003
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Senior Member |
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>> Assume you have a hexadecimal number stored as a string. How do you
>> convert this string to a numeric data type? I can easily convert a
>> number into a hex string, but how do you go the other way?
>>
>> -Mike
>
>
> I think you can use READS with the FORMAT keyword.
Yep. That is exactly what I was trying to find. Thanks. I knew that
it had to be in IDL somewhere, but I just couldn't figure out which
magic searches would take me to the right area of the documentation.
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| Re: Convert hex string to number [message #44566 is a reply to message #44342] |
Fri, 24 June 2005 15:02  |
Michael Wallace
Messages: 409
Registered: December 2003
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Senior Member |
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>> Assume you have a hexadecimal number stored as a string. How do you
>> convert this string to a numeric data type? I can easily convert a number
>> into a hex string, but how do you go the other way?
>>
>> -Mike
>
>
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> IDL> s = 'f'
>
> IDL> reads, s,out,format='(z)'
>
> IDL> help,out
>
> OUT FLOAT = 15.0000
It seems that when the hex numbers get so big, I start losing precision
on the conversion. I have tried a number of different ideas with the
format codes, but nothing has worked so far. It appears that reads
always stores the output value as a float despite how big the input
number is. Is there a way to for it to use double or long on the
conversion?
IDL> reads, '1234abcd', output, format = '(Z)'
IDL> print, output, FORMAT = '(I10)'
305441728
IDL> reads, '1234abce', output, format = '(Z)'
IDL> print, output, FORMAT = '(I10)'
305441728
IDL> reads, '1234abcf', output, format = '(Z)'
IDL> print, output, FORMAT = '(I10)'
305441728
Something is not right with the above picture...
-Mike
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