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Re: easy question [message #45756 is a reply to message #16325]

Thu, 06 October 2005 11:27

Michael Wallace
Messages: 409
Registered: December 2003

Senior Member

You can use a switch or case statement in this case. You can do
something like the following

case 1 of
(x eq 1): print, 'Test 1'
(x eq 2): print, 'Test 2'
(x eq 3): print, 'Test 3'
(x eq 4): print, 'Test 4'
endcase

I'm looking for the first expression that evaluates to true (1). Each
of the expressions are evaluated in turn and the statement associated
with the first expression that evaluates to true is run. If this same
logic were written in a language such as C, it would look like this:

if (x == 1) printf("Test 1\n")
else if (x == 2) printf("Test 2\n")
else if (x == 3) printf("Test 3\n")
else if (x == 4) printf("Test 4\n");

The case construct I used at the top doesn't exist in C or other
languages because there's usually a requirement that the values in the
case or switch must be constants rather than expressions.

Hope that helps,
-Mike

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[Message index]

		Easy question? By: colinr on Wed, 14 July 1999 00:00
		Re: easy question By: Richard French on Fri, 07 October 2005 12:58
		Re: easy question By: mperrin+news on Thu, 06 October 2005 19:48
		Re: easy question By: ChiChiRuiz@gmail.com on Thu, 06 October 2005 14:55
		Re: easy question By: Haje Korth on Thu, 06 October 2005 11:21
		Re: easy question By: Michael Wallace on Thu, 06 October 2005 11:27

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