| Re: Displaying three images simultaneously (using Object Graphics) [message #46222 is a reply to message #46217] |
Tue, 08 November 2005 12:34   |
Dick Jackson
Messages: 347
Registered: August 1998
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Senior Member |
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"Karl Schultz" <k____schultz@rsinc.com> wrote in message
news:pan.2005.11.08.19.05.56.672000@rsinc.com...
> I should point out that starting with IDL 6.2, IDL renders images using
> texture-mapped polygons, doing some of the steps above for you. Further,
> there is a new TRANSFORM_MODE property that will treat the image as a
> polygon during transforms, instead of just transforming the opposite
> corners and making a new 2D box from the new corner locations.
Well, how about that. Thanks for the tip, Karl. My new example would then
be:
im1=Obj_New('IDLgrImage', BytScl(BIndGen(3, 10, 10)), Location=[-10,10], $
Transform_Mode=1)
im2=Obj_New('IDLgrImage', BytScl(RandomU(seed, 3, 10, 10)), $
Transform_Mode=1)
im3=Obj_New('IDLgrImage', 255B-BytScl(BIndGen(3, 10, 10)), Location=[10,10],
$
Transform_Mode=1)
myModel = Obj_New('IDLgrModel')
myModel->Add, [im1, im2, im3]
XObjView, myModel
Another advantage of this is that we get away from the IDLgrPolygon texture
map's required use of image sizes that are a power of two (the images were
resampled to 16x16 in my previous example)
I see now that this whole issue is covered well in online help:
Programmer's Guides:
Object Programming:
Working with Image Objects:
Positioning Image Objects in a View
Cheers,
--
-Dick
Dick Jackson / dick@d-jackson.com
D-Jackson Software Consulting / http://www.d-jackson.com
Calgary, Alberta, Canada / +1-403-242-7398 / Fax: 241-7392
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