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Re: linear fit y=ax [message #46667]

Wed, 07 December 2005 09:47

mmeron
Messages: 44
Registered: October 2003

Member

In article <1133972085.075357.230360@z14g2000cwz.googlegroups.com>, lajam@caramail.com writes:
> Hello,
>
> I have a very easy question but I didn't find the answer in the IDL
> reference guide. I want to fit data with a linear fit y=ax. I want to
> impose my fit to pass by zero. I have looked at the linfit, regress,
> ... functions and I didn't understand how to adapt these functions for
> my problem. I have tried with regress:
> result=regress(desired_value,calculated_value,weigths) but I'm not sure
> that it's the regular way to obtain calculated_value=A*desired_value.
> Could someone help me, please?
>
You can look in my library, MIDL, on the RSI user contributions page.
Chack out the routine LINFIT_MM. It'll do just what you ask for (and
much more)

Mati Meron | "When you argue with a fool,
meron@cars.uchicago.edu | chances are he is doing just the same"

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		Re: linear fit y=ax By: mmeron on Wed, 07 December 2005 09:47
		Re: linear fit y=ax By: Paolo Grigis on Wed, 07 December 2005 08:48
		Re: linear fit y=ax By: Paolo Grigis on Wed, 07 December 2005 08:32

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