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Re: Histogram quickie [message #51935 is a reply to message #51793]

Fri, 08 December 2006 14:38

JD Smith
Messages: 850
Registered: December 1999

Senior Member

On Fri, 08 Dec 2006 12:55:56 -0600, Christopher Thom wrote:

> Hi all,
>
> I'm a long time where() fan, but trying to learn to wield this histogram
> beast. I'm working on an algorithm, and would like a way to divide an
> array of values into two bins, such that the sum of each bin is roughly
> equal. The values have no fixed distribution, so I expect the bin sizes to
> be non-uniform.
>
> This sort of problem seems an ideal place to start earning my histogram
> badge, but I have to confess to only being able to think of
> brute-force-type solutions. Any suggestions?

Probably WHERE will serve you well:

IDL> t=total(a,/CUMULATIVE)
IDL> bin1=where(t lt t[n_elements(a)-1]/2,COMPLEMENT=bin2)

Of course, there are many ways to divide values such that they fall into
two roughly equal bins (n choose 2), some of which may be better than
others.

JD

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[Message index]

		Histogram quickie By: Christopher Thom on Fri, 08 December 2006 10:55
		Re: Histogram quickie By: Christopher Thom on Mon, 11 December 2006 07:49
		Re: Histogram quickie By: Braedley on Fri, 08 December 2006 18:09
		Re: Histogram quickie By: JD Smith on Fri, 08 December 2006 14:38

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