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Re: Cut down a big file into several files based on its a column. [message #53061 is a reply to message #53012]

Fri, 16 March 2007 08:34

Maarten[1]
Messages: 176
Registered: November 2005

Senior Member

On Mar 16, 9:46 am, "DirtyHarry" <kim20...@gmail.com> wrote:
> Thanks, Maarten... but... T.T
>
> Is there any way to do this in Windows version of IDL?

This was my first try. It doesn't quite work, because I can't get the
format statment right (how do you insert linebreaks?)

;;; failed attempt.
file='hum.txt'
ndata=file_lines(file)
data=intarr(28, ndata)

for year=2000,2005 do begin
openw, unit, string(format="('HumNWS_',I04,'.txt')", year), /get_lun

idx = where(data[1,*] eq year, cnt)
if cnt gt 0 then begin
fmt=string(format="('(',I04,'(28i6))')", cnt)
; it would ne neat if IDL actually allowed to add newlines between
the blocks here.
printf, unit, format=fmt, data[*,idx]
endif

free_lun, unit
endfor
end

;;; Second attempt: use explicit for loop.
file='hum.txt'
ndata=file_lines(file)
data=intarr(28, ndata)

for year=2000,2005 do begin
openw, unit, string(format="('HumNWS_',I04,'.txt')", year), /get_lun

idx = where(data[1,*] eq year, cnt)
fmt='(28i6)'
if cnt gt 0 then $
for ii=0,cnt-1 do $
printf, unit, format=fmt, data[*,idx[ii]]

free_lun, unit
endfor
end

HTMH,

Maarten

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[Message index]

		Cut down a big file into several files based on its a column. By: kim20026 on Tue, 13 March 2007 18:22
		Re: Cut down a big file into several files based on its a column. By: Maarten[1] on Fri, 16 March 2007 08:54
		Re: Cut down a big file into several files based on its a column. By: Maarten[1] on Fri, 16 March 2007 08:34
		Re: Cut down a big file into several files based on its a column. By: Peter Clinch on Fri, 16 March 2007 03:24

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