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Re: Multiplication changes array dimensions since a scalar and a 1x1 array are not the same [message #53259]

Sat, 31 March 2007 21:13

swingnut
Messages: 30
Registered: September 2005

Member

Haha. So, all those SIZE statements sunk in. Here's the workaround I
came up with.

;SIZE of testVirtHeight =
; 1 1 4 1

;SIZE of referenceHeight =
; 0 4 1

deltaVirtHeight = testVirtHeight - referenceHeight

signOfDifference -> 1x1 array instead of a scalar.

adjustmentIncrement = adjustmentIncrement * signOfDifference

adjustmentIncrement -> 1x3 array before operation, 1x1 array
afterwards

SOLUTION: Extract scalar from array element -> testVirtHeight =
testVirtHeight[0,0]

----------

Clearly my calculation of deltaVirtHeight assumed that you could treat
a 1x1 scalar, while IDL is treating them as different types of
variables during array multiplications. Now, why a scalar and a 1x1
array are different escapes me, but at least I've found this
workaround and can continue on. And hopefully knowing about this might
help someone else.

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Re: Multiplication changes array dimensions since a scalar and a 1x1 array are not the same

By: swingnut on Sat, 31 March 2007 21:13

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