| Re: search routine [message #54381 is a reply to message #54247] |
Fri, 01 June 2007 08:24   |
Laurens
Messages: 41
Registered: May 2006
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Member |
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Paolo Grigis wrote:
>
>
> Laurens wrote:
>> Paolo Grigis wrote:
>>>
>>>
>>> Laurens wrote:
>>>> Hi folks,
>>>>
>>>> From Martin Schultz (posted in 1999) I found the following
>>>> array-search algorithm which seems to do a fine job.
>>>> Except that i'm not able to catch the first element in the array.
>>>>
>>>> Example:
>>>>
>>>> Array = [0,80,100,120,180,300]
>>>> result = search, Array, 4.53
>>>>
>>>> It should return index 0, if I understand it correctly, but it
>>>> returns 1 instead. Now I don't quite follow the logic of the
>>>> function, so maybe someone for which it's easy to see can help me in
>>>> the right direction?
>>>
>>> You could use the built-in function value_locate instead:
>>>
>>> result=value_locate(array,4.53)
>>>
>>> which returns 0.
>>>
>>> Ciao,
>>> Paolo
>>>
>> though i'm noticing that it takes its ground number to be returned.
>> If my array has [0,10,20,30] and i'm searching for 18, it will return
>> 10. Now its just that would want to get 20 instead of 10 :)
>
> well, in that case, just increase the index of the returned
> value by one (though you'd better check that it wasn't the
> *last* element...).
>
> Ciao,
> Paolo
>
>>
>> regards, Laurens
haha, that sounds like a plausible solution, but that would get a result
of 13 to become the 3rd index (2), when it should be the second.. It
just needs to mean the result before it compares the value, but i assume
that's not something which can be done without rewriting it?
Cheers, Laurens
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