| Re: readf,1,format= ...... [message #57387] |
Sat, 08 December 2007 14:01  |
David Fanning
Messages: 11724
Registered: August 2001
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Senior Member |
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woopik@interia.pl writes:
> i have a question
> i have in a txt file some data
> 48883 149.55579541 12.44483936
> .... .... ....
> when i read a entire line
> line=''
> readf,1,line
> print,line
> i get a good output
> 48883 149.55579541 12.44483936
>
> but when i read data like this
> ttab = MAKE_ARRAY(nlines,3,/DOUBLE)
> ...
> FMTp='(I5,2X,D13.8,2X,D13.8)'
> for i=1,nlines do begin
> READF,1,FORMAT=FMT,l1,l2,l3
> ttab[i-1,0]=l1 & ttab[i-1,1]=l2 & ttab[i-1,2]=l3
> endfor
> and i print them
> print,FORMAT=FMTp,ttab[0,0], ttab[0,1],ttab[0,2]
> i get
> 48883 149.55580139 12.44483948
> and this is not the same it should be
> 48883 149.55579541 12.44483936
>
> why ?
Well, if this code is correct, I would say because you didn't
use the same format on your READF command as you did on your
PRINT command. So, I think the numbers were read in as floats,
not doubles. If I use the same format both places, no worries. :-)
Cheers,
David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")
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| Re: readf,1,format= ...... [message #57476 is a reply to message #57387] |
Sun, 09 December 2007 02:31  |
woopik
Messages: 18
Registered: September 2007
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Junior Member |
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> I would say because you didn't use the same format on your
> READF command as you did on your PRINT command.
i dont understand your tip :(
i am using the same FMTp format for both
Wojtek
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