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Re: Multi bands mean [message #58660 is a reply to message #58658]

Fri, 08 February 2008 09:15

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

David Fanning writes:

>> mean_image=total(multi_bands_image, 3, /nan) / total(finite(a),3)
>
> Whoops! Of course, a is the "universal variable", and in
> your case will be equal to multi_bands_image. :-)

Whoops! Whoops! (I'm trying to get ready for an international
trip here...)

I *think* TOTAL will cast the finite array, which is
a byte array, into floats, but you better make sure of that.
I don't have time to. :-)

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")

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[Message index]

		Re: Multi bands mean By: jujo on Fri, 08 February 2008 09:44
		Re: Multi bands mean By: David Fanning on Fri, 08 February 2008 09:15
		Re: Multi bands mean By: David Fanning on Fri, 08 February 2008 09:09
		Re: Multi bands mean By: David Fanning on Fri, 08 February 2008 09:05

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