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Re: matrix division [message #60543 is a reply to message #60444] Fri, 23 May 2008 09:41 Go to previous messageGo to previous message
Jean H. is currently offline  Jean H.
Messages: 472
Registered: July 2006
Senior Member
>> c = a/(b + replacement_value*(abs(b) lt epsilon))
>
> Ooooo, good one, Jean.

on the other hand, doing this, when 'b' is 0, would lead to 'c = a /
replacement_value'... so in 'c', you would get different results as 'a'
varies..

Jean
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