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Re: how to draw contour with continue color? [message #63661 is a reply to message #63657]

Sat, 15 November 2008 20:13

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

xqinshan writes:

> Hi, I use "contour...nlevels=..../fill" to get contour plot. The color
> variation is seperated. Although if I set nlevels=50 or more it looks
> better, but the contour color is not continuous. When I donot set
> nleves for "colorbar", the color of colorbar is continuous.But how can
> I do for contour?

You want an image, not a filled contour plot.

data = Dist(300)
step = (Max(data) - Min(data)) / 16.
levels = Indgen(16) * step + Min(data)
Device, Decomposed=1
CTLoad, 4, /Brewer
pos = [0.15, 0.15, 0.9, 0.75]
Erase, Color=FSC_Color('ivory')
TVImage, BytScl(data), POSITION=pos
Contour, data, /NOERASE, POSITION=pos, XSTYLE=1, YSTYLE=1, $
LEVELS=levels, COLOR=FSC_Color('black'), $
C_LABEL=Replicate(1, 16)
Colorbar, NCOLORS=256, RANGE=[Min(data), Max(data)], DIVISIONS=4, $
POSITION=[0.15, 0.8, 0.9, 0.85], /TOP, COLOR=FSC_Color('black')

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")

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[Message index]

		Re: how to draw contour with continue color? By: xqinshan on Mon, 17 November 2008 04:46
		Re: how to draw contour with continue color? By: David Fanning on Sun, 16 November 2008 07:51
		Re: how to draw contour with continue color? By: David Fanning on Sun, 16 November 2008 07:35
		Re: how to draw contour with continue color? By: xqinshan on Sun, 16 November 2008 07:12
		Re: how to draw contour with continue color? By: David Fanning on Sun, 16 November 2008 06:02
		Re: how to draw contour with continue color? By: xqinshan on Sun, 16 November 2008 05:34
		Re: how to draw contour with continue color? By: xqinshan on Sun, 16 November 2008 00:57
		Re: how to draw contour with continue color? By: David Fanning on Sat, 15 November 2008 20:13
		Re: how to draw contour with continue color? By: R.G. Stockwell on Sat, 15 November 2008 19:57

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