| Re: -9999 datas! [message #65591] |
Wed, 11 March 2009 23:03 |
d.poreh
Messages: 406
Registered: October 2007
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Senior Member |
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Thank you very much.
Cheers
On Mar 11, 6:09 pm, ed.schm...@gmail.com wrote:
> Well, you could replace all of your -9999 values with the not-a-
> number !values.f_nan (called NaN), and then selectively replace each
> NaN using mean(w,/nan) in windows whose indices are specified by w.
> (When nan is set in the mean function, any array elements with an NaN
> are skipped.) How big the window must be depends on how closely spaced
> the -9999 values are, and how much averaging you wish to do.
>
> There may be "canned" routines that will do the entire job for you,
> but I don't know of any myself.
>
> Ed Schmahl
>
> d.po...@gmail.com wrote:
>> Folks
>> I have a problem. I have an image with some -9999 data I want to
>> replace these pixels by average of four neighbours. Any help? How come
>> do this if -9999s are in the edges?
>> Cheers
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| Re: -9999 datas! [message #65613 is a reply to message #65591] |
Wed, 11 March 2009 10:09  |
ed.schmahl
Messages: 11
Registered: October 2008
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Junior Member |
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Well, you could replace all of your -9999 values with the not-a-
number !values.f_nan (called NaN), and then selectively replace each
NaN using mean(w,/nan) in windows whose indices are specified by w.
(When nan is set in the mean function, any array elements with an NaN
are skipped.) How big the window must be depends on how closely spaced
the -9999 values are, and how much averaging you wish to do.
There may be "canned" routines that will do the entire job for you,
but I don't know of any myself.
Ed Schmahl
d.po...@gmail.com wrote:
> Folks
> I have a problem. I have an image with some -9999 data I want to
> replace these pixels by average of four neighbours. Any help? How come
> do this if -9999s are in the edges?
> Cheers
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