comp.lang.idl-pvwave archive: archive

Home » Public Forums » archive » indexing

Show: Today's Messages :: Show Polls :: Message Navigator
E-mail to friend

indexing [message #65929]

Wed, 01 April 2009 18:12

Jeremy Bailin
Messages: 618
Registered: April 2008

Senior Member

I swear I've seen this come up within the past few months, but I can't
find it, so here goes:

Let's say I have a 3D array - think of it as x,y,z if you want. I have
a list of x,y pairs and I want to perform on operation on a given
range in z (say z1:z2) and each x,y pair. For a simple example, let's
say I just want them all up. So, if the following were my x,y pairs:
3 4
2 1
3 7
and my z range was 1:3 then I want
array[3,4,1]+array[3,4,2]+array[3,4,3]
+array[2,1,1]+array[2,1,2]+array[2,1,3]
+array[3,7,1]+array[3,7,2]+array[3,7,3]

Is there a simple representation for this? My standard solution, if
pair is an npair x 2 array containing the x,y pairs, looks something
like this:
nz=z2-z1+1
zindices=rebin(reform(z1+lindgen(nz),1,nz), npair,nz)
xindices=rebin(pair[*,0],npair,nz)
yindices=rebin(pair[*,1],npair,nz)
answer = total(array[xindices,yindices,zindices])

...but if nz and npair are large, generating all of those 2D index
arrays is really wasteful. The following also works:

answer = total(array[pair[*,0],pair[*,1],z1:z2] * rebin(identity
(npair,npair,nz)))

but again generates 2 intermediate npair x npair x nz arrays that are
wasteful if npair is large.

Any takers?

-Jeremy.

Report message to a moderator

[Message index]

		indexing By: Jeremy Bailin on Wed, 01 April 2009 18:12
		Re: indexing By: JDS on Wed, 08 April 2009 15:35
		Re: indexing By: Jeremy Bailin on Thu, 02 April 2009 12:20

Previous Topic:	CATCH error problem
Next Topic:	Is there a function to calculate the determinant of a N×N matrix?

-=] Back to Top [=-

[ Syndicate this forum (XML) ] [

] [

]

Current Time: Wed Oct 08 17:34:46 PDT 2025

Total time taken to generate the page: 0.00567 seconds