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Re: how to check if a loop fails [message #66259] Sun, 26 April 2009 17:50 Go to previous message
xiao zhang is currently offline  xiao zhang
Messages: 81
Registered: June 2008
Member
On Apr 26, 2:36 pm, Vince Hradil <vincehra...@gmail.com> wrote:
> On Apr 26, 11:21 am, xiao <littledd...@gmail.com> wrote:
>
>
>
>> hmm.....David, I tried the processbar like this:
>
>> for j=0,7 do begin
>
>> progressBar = Obj_New("SHOWPROGRESS", /AutoUpDate, Delay=5,
>> Steps=20)
>> progressBar->Start
>> Obj_Destroy, progressBar
>
>> .......
>
>> endfor
>
>> And it does move for the first step but it disappeared after that.
>> Sigh.....
>
>> Xiao
>
>> On Apr 26, 10:49 am, David Fanning <n...@dfanning.com> wrote:
>
>>> xiao writes:
>>>> I have a loop including several functions and when I run the
>>>> program, I wait for a long time and the loop is still running. I
>>>> wonder if the loop is already dead. Any ideas how I can check it?
>
>>> Checking for error messages comes to mind. :-)
>
>>> You could also try a progress bar. It it doesn't move for
>>> 5 or 10 minutes you might conclude your loop was dead:
>
>>> http://www.dfanning.com/widget_tips/show_progress.html
>
>>> Cheers,
>
>>> David
>>> --
>>> David Fanning, Ph.D.
>>> Fanning Software Consulting, Inc.
>>> Coyote's Guide to IDL Programming:http://www.dfanning.com/
>>> Sepore ma de ni thui. ("Perhaps thou speakest truth.")
>
> progressBar = Obj_New("SHOWPROGRESS", /AutoUpDate, Delay=5,Steps=20)
> progressBar->Start
> for j=0,7 do begin
> .......
> endfor
> Obj_Destroy, progressBar
>
> But even easier would be to:
> 1- step through the code using the debugger
> 2- add print statements to inspect variables
>
> for j=0,n-1 do begin
> print, 'Step ' + strtrim(j+1,2) + ' of ' + strtrim(n,2) + ' steps'
> .......
> endfor

haha, Thank you very much
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