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Re: bad column in image [message #66706 is a reply to message #66703]

Wed, 03 June 2009 09:11

David Fanning
Messages: 11724
Registered: August 2001

Senior Member

Amanda writes:

> I was just using the where function, like this: arr(where(arr[1440,*]
> GT 1000))=3Dmean(arr) but I don't know if that's how I should be doing
> it.

No, that's not the way you should be doing it. :-)

I would do it like this:

badcol = arr[1440,*]
indices = Where(badcol GT 1000, count)
IF count GT 0 THEN badcol[indices] = Mean(arr)
arr[1440,*] = badcol

Using the mean of the array is sketchy. Perhaps some
kind of interpolation method would be better:

http://www.dfanning.com/math_tips/easyinterp.html

Cheers,

David
--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")

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[Message index]

		Re: bad column in image By: Jean H. on Wed, 03 June 2009 09:48
		Re: bad column in image By: David Fanning on Wed, 03 June 2009 09:11
		Re: bad column in image By: Amanda on Wed, 03 June 2009 09:03
		Re: bad column in image By: David Fanning on Tue, 02 June 2009 19:08
		Re: bad column in image By: Amanda on Fri, 05 June 2009 12:22

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