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Re: The IDL way: Find last non-zero value [message #67726]

Mon, 24 August 2009 19:53

Jeremy Bailin
Messages: 618
Registered: April 2008

Senior Member

On Aug 23, 11:39 pm, Gianguido <gianguido.cia...@gmail.com> wrote:
> Another option - given that your array contains only positive numbers,
> I thought total(array, 1, /cumulative) could be handy:
>
> array=[ [1,2, 0, 1, 0, 0],$
> [0, 0, 3,4, 1, 0],$
> [1, 5,6, 0, 0, 0],$
> [0,0,0,0,0,0], $
> [1, 0,0,0,0,0] ]
>
> tc=total(array, 1, /cumulative)
> blah=max(tc, dim=1, w)
> result=(array_indices(tc,w))[0,*]
>
> t=total(array, 1)
> result[where(t eq 0)]=-1
>
> Gianguido

You can substitute array with abs(array) or (array ne 0) if there are
negative values, so this method is completely general!

-Jeremy.

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[Message index]

		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 19:53
		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 19:43
		Re: The IDL way: Find last non-zero value By: penteado on Mon, 24 August 2009 18:35
		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 17:12
		Re: The IDL way: Find last non-zero value By: Eric Hudson on Mon, 24 August 2009 13:42
		Re: The IDL way: Find last non-zero value By: cgguido on Sun, 23 August 2009 20:39
		Re: The IDL way: Find last non-zero value By: penteado on Sun, 23 August 2009 19:10
		Re: The IDL way: Find last non-zero value By: Chris[6] on Sun, 23 August 2009 17:32

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