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Re: The IDL way: Find last non-zero value [message #67744 is a reply to message #67737]

Sun, 23 August 2009 20:39

cgguido
Messages: 195
Registered: August 2005

Senior Member

Another option - given that your array contains only positive numbers,
I thought total(array, 1, /cumulative) could be handy:

array=[ [1,2, 0, 1, 0, 0],$
[0, 0, 3,4, 1, 0],$
[1, 5,6, 0, 0, 0],$
[0,0,0,0,0,0], $
[1, 0,0,0,0,0] ]

tc=total(array, 1, /cumulative)
blah=max(tc, dim=1, w)
result=(array_indices(tc,w))[0,*]

t=total(array, 1)
result[where(t eq 0)]=-1

Gianguido

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[Message index]

		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 19:53
		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 19:43
		Re: The IDL way: Find last non-zero value By: penteado on Mon, 24 August 2009 18:35
		Re: The IDL way: Find last non-zero value By: Jeremy Bailin on Mon, 24 August 2009 17:12
		Re: The IDL way: Find last non-zero value By: Eric Hudson on Mon, 24 August 2009 13:42
		Re: The IDL way: Find last non-zero value By: cgguido on Sun, 23 August 2009 20:39
		Re: The IDL way: Find last non-zero value By: penteado on Sun, 23 August 2009 19:10
		Re: The IDL way: Find last non-zero value By: Chris[6] on Sun, 23 August 2009 17:32

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