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Re: L-moments [message #75407 is a reply to message #75329] Mon, 28 February 2011 04:13 Go to previous messageGo to previous message
Gray is currently offline  Gray
Messages: 253
Registered: February 2010
Senior Member
On Feb 28, 6:43 am, chris <rog...@googlemail.com> wrote:
> On 25 Feb., 16:25, Mark Shephard <mark.w.sheph...@gmail.com> wrote:
>
>> Hi,
>
>> I was wondering if anyone has anyone develope IDL routines for the
>> method of L-moments?
>
>> Thanks,
>> Mark
>
> Hi Mark,
> something like this?
>
> function cr_binomial,n,m
>         n1=1d   &   m1=1d & n1m1=1d
>         for i=1d,n do n1*=i
>         for i=1d,m do m1*=i
>         for i=1d,(n-m) do n1m1*=i
>         return,n1/(m1*n1m1)
> end
>
> function cr_l_moment,dat
> n=n_elements(dat)
> l1 = total(dat,/double)/cr_binomial(n,1)
> l2=0d &l3=0d &l4=0d
> for i=1d,n do begin
>         b1      =       cr_binomial(i-1,1d)
>         b2      =       cr_binomial(n-i,1d)
>         b3      =       cr_binomial(i-1,2d)
>         b4      =       cr_binomial(n-i,2d)
>         b5      =       cr_binomial(i-1,3d)
>         b6      =       cr_binomial(n-i,3d)
>         l2+=(b1-b2)*dat[i-1l]
>         l3+=(b3-2*b1*b2+b4)*dat[i-1l]
>         l4+=(b5-3*b3*b2+3*b1*b4+b6)*dat[i-1l]
> endfor
> l2*=0.5d /cr_binomial(n,2d )
> l3*=(1d / 3d )/cr_binomial(n,3d )
> l4*=(1d / 4d )/cr_binomial(n,4d )
> return,{l1:l2,l2:l2,l3:l3,l4:l4}
> end
>
> IDL> r=randomu(seed,5,5)
> IDL> inf=cr_l_moment(r)
> IDL> print,float(inf)
> { -0.000558181 -0.000558181   -0.0111168     0.212071}
>
> Cheers
>
> CR

I have no idea what L-moments are, but do you really need to use all
the FOR-loops?

function cr_binomial,n,m
n1 = product(dindgen(n)+1)
m1 = product(dindgen(m)+1)
n1m1 = product(dindgen(n-m)+1)
return, n1/(m1*n1m1)
end
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