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Re: polar_cgContour? [message #77392 is a reply to message #77390]

Thu, 25 August 2011 14:49

Matteo
Messages: 28
Registered: August 2011

Junior Member

David,

I managed to run your polarcontour routine. I see that you're
basically laying the 2D-array as a blanket, centered, over the "North
Pole". What I really meant is to use the x-axis (e.g, [0,90]) as the
polar angle, the y-axis ([0,180]) as the azimuthal angle. The
horizontal line going through the center of the square 2D-array should
become the vertical line in the (semi-)circular polar plot (90 deg of
azimuth). In other words, the 2D-array gets "opened" like a fan while
the left side of the square (polar angle=0 deg) collapses into a point
(the origin). These things should be clear in the figure I attached in
my email.

'best,
m

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[Message index]

		Re: polar_cgContour? By: Matteo on Fri, 26 August 2011 14:21
		Re: polar_cgContour? By: David Fanning on Thu, 25 August 2011 16:31
		Re: polar_cgContour? By: Matteo on Thu, 25 August 2011 16:15
		Re: polar_cgContour? By: David Fanning on Thu, 25 August 2011 15:57
		Re: polar_cgContour? By: David Fanning on Thu, 25 August 2011 15:51
		Re: polar_cgContour? By: Matteo on Thu, 25 August 2011 15:32
		Re: polar_cgContour? By: Matteo on Thu, 25 August 2011 15:09
		Re: polar_cgContour? By: David Fanning on Thu, 25 August 2011 14:59
		Re: polar_cgContour? By: Matteo on Thu, 25 August 2011 14:49
		Re: polar_cgContour? By: David Fanning on Thu, 25 August 2011 14:38
		Re: polar_cgContour? By: Matteo on Thu, 25 August 2011 14:28
		Re: polar_cgContour? By: David Fanning on Wed, 24 August 2011 20:15
		Re: polar_cgContour? By: David Fanning on Wed, 24 August 2011 14:10

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