| IDL QUESTION HELP [message #79774] |
Tue, 03 April 2012 01:42  |
zeeshan
Messages: 1
Registered: April 2012
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Junior Member |
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respected sir,
i am a beginner in IDL.
my problem is that i have to open an image which is in " .bin " format
in idl.
i have converted it into ASCII format but stil its not opening.
how to open a DN value image in idl.
there is some other problem also.
as it is a satellite data image so its showing the dimension as "
Array[14293248] "
which comes out to be " 1184 * 3018 * 4 " but its dimension is
in .CSV format which is " 1184 * 3018 "
so how come this multiplication factor of " 4 " is generated.
In MATLAB i can open the same data after converting it into text or
".csv" format and than importing it
but the problem is the data size is huge so its not possible to work
in matlab.
is there any way to do the same procedure in IDL
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| Re: IDL QUESTION HELP [message #79833 is a reply to message #79774] |
Fri, 06 April 2012 15:38  |
b.janssen.nl
Messages: 2
Registered: April 2012
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Junior Member |
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Op dinsdag 3 april 2012 10:42:15 UTC+2 schreef zeeshan het volgende:
> respected sir,
> i am a beginner in IDL.
> my problem is that i have to open an image which is in " .bin " format
> in idl.
> i have converted it into ASCII format but stil its not opening.
> how to open a DN value image in idl.
>
> there is some other problem also.
> as it is a satellite data image so its showing the dimension as "
> Array[14293248] "
> which comes out to be " 1184 * 3018 * 4 " but its dimension is
> in .CSV format which is " 1184 * 3018 "
> so how come this multiplication factor of " 4 " is generated.
>
> In MATLAB i can open the same data after converting it into text or
> ".csv" format and than importing it
> but the problem is the data size is huge so its not possible to work
> in matlab.
> is there any way to do the same procedure in IDL
Hello Zeesan,
You can try to make the (a test) file available(dropbox link) and I'm happy to trail and error it on bases of just the fixed x&y, probably it is like .tiff per pixel a bigger contrast than [255,255,255], maybe [x,y,value(gray only 0..1024], so not true color[x,y,[r,g,b]]
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