Re: CMIP5 model output [message #83859] |
Thu, 11 April 2013 15:27 |
DavidF[1]
Messages: 94 Registered: April 2012
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siumt...@gmail.com wrote:
> how can you convert CMIP5 model output time to the Julian day?
I don't know how CMIP5 does this, but normally time is expressed as "number of days since 1600-01-01", or something like that. So, to create the correct Julian day number you do this:
time = time + Julday(1,1,1600,0,0,0)
Then, when you want months, days, and years, you convert these Julian values with CatDat:
CatDat, time, month, day, year
Cheers,
David
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