| Stregex question - extracting substring [message #87007] |
Thu, 19 December 2013 12:44  |
PMan
Messages: 61
Registered: January 2011
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Member |
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I am trying to extract a substring after a colon. My string looks like:
xxxxxx:yyyyyyyyy
where x's can be spaces, upper and lower case letters
then there's the colon
and finally the y's, which can be pretty much anything and will often include colons (which is why strsplit("xxxxxx:yyyyyyyyy", ":") won't work for me here)
I just want the yyyyyyyyyy part and have been trying to extract it with stregex, but no luck. But before I give up and will try a different approach, does anyone know how to construct a regular expression for IDL that would extract just the yyyy.. part with stregex?
Thanks for your time.
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| Re: Stregex question - extracting substring [message #87008 is a reply to message #87007] |
Thu, 19 December 2013 12:53  |
John Correira
Messages: 25
Registered: August 2011
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Junior Member |
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On 12/19/2013 03:44 PM, Paul Mallas wrote:
> I am trying to extract a substring after a colon. My string looks
> like:
>
> xxxxxx:yyyyyyyyy
>
> where x's can be spaces, upper and lower case letters
>
> then there's the colon
>
> and finally the y's, which can be pretty much anything and will often
> include colons (which is why strsplit("xxxxxx:yyyyyyyyy", ":") won't
> work for me here)
>
> I just want the yyyyyyyyyy part and have been trying to extract it
> with stregex, but no luck. But before I give up and will try a
> different approach, does anyone know how to construct a regular
> expression for IDL that would extract just the yyyy.. part with
> stregex?
>
> Thanks for your time.
>
Not a stregex solution, but I think something like
strjoin((strsplit(string,':',/extract))[1:*],':')
would do it.
John
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| Re: Stregex question - extracting substring [message #87010 is a reply to message #87008] |
Thu, 19 December 2013 13:09 |
Helder Marchetto
Messages: 520
Registered: November 2011
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Senior Member |
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On Thursday, December 19, 2013 9:53:08 PM UTC+1, John Correira wrote:
> On 12/19/2013 03:44 PM, Paul Mallas wrote:
>
>> I am trying to extract a substring after a colon. My string looks
>
>> like:
>
>>
>
>> xxxxxx:yyyyyyyyy
>
>>
>
>> where x's can be spaces, upper and lower case letters
>
>>
>
>> then there's the colon
>
>>
>
>> and finally the y's, which can be pretty much anything and will often
>
>> include colons (which is why strsplit("xxxxxx:yyyyyyyyy", ":") won't
>
>> work for me here)
>
>>
>
>> I just want the yyyyyyyyyy part and have been trying to extract it
>
>> with stregex, but no luck. But before I give up and will try a
>
>> different approach, does anyone know how to construct a regular
>
>> expression for IDL that would extract just the yyyy.. part with
>
>> stregex?
>
>>
>
>> Thanks for your time.
>
>>
>
>
>
>
>
> Not a stregex solution, but I think something like
>
>
>
> strjoin((strsplit(string,':',/extract))[1:*],':')
>
>
>
> would do it.
>
>
>
> John
Hi John
I just answered and the original post was deleted, so my answer was dumped.
My solution was: strmid(str,strpos(str,':')+1)
It's good as long as there is at least one ':'. (if necessary one can check for it...).
Cheers,
h
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| Re: Stregex question - extracting substring [message #87016 is a reply to message #87013] |
Fri, 20 December 2013 07:53 |
PMan
Messages: 61
Registered: January 2011
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Member |
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On Thursday, December 19, 2013 5:31:40 PM UTC-5, Phillip Bitzer wrote:
> OK, how about a STREGEX solution:
>
>
>
> str = ['xxxxxxx:yyy', 'xxxxxxx:yyyyyyy', 'x:yyyy'] ;define the string array
>
>
>
> yStrColon = STREGEX(str, ':.+$', /EXTRACT) ;get everything past the colon, including the colon
>
>
>
> yStr = STRMID(yStrColon, 1) ;strip the colon
>
>
>
> About that regular expression:
>
>
>
> : get the substring starting with the colon
>
> .+ get one or more instances of the "dot" (so, any character)
>
> $ anchor at the end of the string
I figured out my solution, just moments after my post (isn't that always the case??) Here is what I did, which is similar to Philip's approach:
I was starting with an array of strings, hence the indices at the end:
x = (stregex(splLines, ':(.*)$' , /extract, /sub))[1, *]
(x = (stregex(splLines, ':(.*)$' , /extract, /sub))[1] for a single string)
The () encapsulates what the /sub extracts and [1] index gets the subexpression only, the 0th element starts with the colon, which I did not want.
Thanks for the reply to my short-lived post!
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