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How do you using the IDL to add a straight line of 45 degrees inclination to scatter plot of the square? [message #92033]

Fri, 02 October 2015 00:06

ristight
Messages: 5
Registered: September 2015

Junior Member

I want to add a line of 45 degrees inclination to scatter diagram using the IDL.
How do you rewrite this program?
Someone help me please.

;Program

pro sactter_plot

x1 = fltarr(3600,1200)
y1 = fltarr(3600,1200)
mvk = fltarr(3600,1200)
nrt = fltarr(3600,1200)

fname1='C:\Users\Desktop\mvk_20150331.txt'
fname2='C:\Users\Desktop\nrt_20150331.txt'
openr,1,fname1
openr,2,fname2
readf,1,x1
readf,2,y1

p=plot(x1,y1,aspect_ratio=1,xrange=[0,2000],yrange=[0,2000], linestyle='none',symbol='star',color='000000'XL,title='20150 331 precipitation',xtitle='mvk precipitation [mm]',ytitle='nrt precipitation [mm]')
close, /all

end

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Re: How do you using the IDL to add a straight line of 45 degrees inclination to scatter plot of the square? [message #92038 is a reply to message #92033]

Fri, 02 October 2015 06:31

Phillip Bitzer
Messages: 223
Registered: June 2006

Senior Member

On Friday, October 2, 2015 at 2:06:46 AM UTC-5, 山本正志 wrote:
> I want to add a line of 45 degrees inclination to scatter diagram using the IDL.
> How do you rewrite this program?
> Someone help me please.

As yourself this: how do you mathematically define a straight line? Then, what does "45 degrees inclination" mean for the slope of the line?

Once you have that, you just overplot this line on your plot.

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