| Screen size factor of two error?! [message #92819] |
Fri, 04 March 2016 16:15  |
David Klassen
Messages: 27
Registered: December 2004
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Junior Member |
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So I'm trying to display an array that has a fairly large size in one dimension, over 2000. No sweat, I say, because OSX tells me that my screen size is 2880x1800 (of course, some of that vertical is taken up by the menu bar).
I tell IDL: window, xs=2420, ys=35
And the window spans my entire display. But when I put the image in that window, I only see half of it.
When I do:
dimensions = GET_SCREEN_SIZE(RESOLUTION=resolution)
PRINT, dimensions, resolution
It tells me:
1440 878
0.026458333 0.026423690
1440*2=2880 and 878*2=1756 (so, 45 pixels for the menu bar, I presume...)
What's up with IDL only using half my actual screen resolution?
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| Re: Screen size factor of two error?! [message #92820 is a reply to message #92819] |
Fri, 04 March 2016 16:32  |
David Klassen
Messages: 27
Registered: December 2004
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Junior Member |
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Never mind... It's not an IDL issue. It's XQuartz.
"As of version 2.7.8, XQuartz does not provide support for high-resolution Retina displays to X11 apps, which run in pixel-doubled mode on high-resolution displays."
On Friday, March 4, 2016 at 4:15:59 PM UTC-8, David Klassen wrote:
> So I'm trying to display an array that has a fairly large size in one dimension, over 2000. No sweat, I say, because OSX tells me that my screen size is 2880x1800 (of course, some of that vertical is taken up by the menu bar).
>
> I tell IDL: window, xs=2420, ys=35
>
> And the window spans my entire display. But when I put the image in that window, I only see half of it.
>
> When I do:
> dimensions = GET_SCREEN_SIZE(RESOLUTION=resolution)
> PRINT, dimensions, resolution
> It tells me:
> 1440 878
> 0.026458333 0.026423690
>
> 1440*2=2880 and 878*2=1756 (so, 45 pixels for the menu bar, I presume...)
>
> What's up with IDL only using half my actual screen resolution?
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