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Re: adding a 4th dimension to 3D array during concatenation [message #92879 is a reply to message #92869]

Wed, 16 March 2016 22:52

Guilherme Gualda
Messages: 2
Registered: March 2016

Junior Member

Hi,

It may not be the most efficient, but it is easy to do what you want if you use reform. In your example, if each array x you create has dimensions [sx, sy, sz], then you can use:

array = [array, reform(x, 1, sx, sy, sz)]

Hope this helps!

Best,

Guil

On Tuesday, March 15, 2016 at 5:37:18 PM UTC-5, Wayana Dolan wrote:
> So outside a loop I start out with an empty array (ex. array=[ ] ). Then each time through the loop, I make an array with 3 dimensions (for example, array x has dimensions[91, 41, 33] ), and then concatinate it to the previous array. (ex. array=[array, x]).
>
> Lets say we run through the loop 16 times. What I'd like as a result is something that has dimensions like this [16, 91, 41, 33].
>
> I'm not sure how to do this... I've looked at IDL coyote's concatenation tutorial, and still am having trouble.
>
> I'm pretty new to coding period, so this is a challenge. Any ideas?

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[Message index]

		adding a 4th dimension to 3D array during concatenation By: wdolan on Tue, 15 March 2016 15:37
		Re: adding a 4th dimension to 3D array during concatenation By: Paul Van Delst[1] on Wed, 16 March 2016 08:00
		Re: adding a 4th dimension to 3D array during concatenation By: Jim Pendleton on Wed, 16 March 2016 18:46
		Re: adding a 4th dimension to 3D array during concatenation By: wlandsman on Wed, 16 March 2016 20:46
		Re: adding a 4th dimension to 3D array during concatenation By: Guilherme Gualda on Wed, 16 March 2016 22:52

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