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Re: generate sequential list [message #93247 is a reply to message #93246] Thu, 19 May 2016 08:31 Go to previous messageGo to previous message
Lajos Foldy is currently offline  Lajos Foldy
Messages: 176
Registered: December 2011
Senior Member
On Thursday, May 19, 2016 at 5:25:31 PM UTC+2, greg...@googlemail.com wrote:
> Is there an elegant way to generate an incremental list, i.e. the list() equivalent of indgen()? Or to convert an array to a list?
>
> cheers,
> Greg

list(indgen(5), /extract)

regards,
Lajos
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