| Where.. Then Loop IDL help [message #93771] |
Thu, 13 October 2016 21:39  |
smnadoum
Messages: 24
Registered: June 2016
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Junior Member |
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Hi,
I am new to IDL world, and was wondering if you can help me create a loop.
I need to create an array by replacing all values in 'a' that are greater than 5 by 20.
c= where(a gt 5) then [c] = 20
Is this the correct way to do it?
Thanks
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| Re: Where.. Then Loop IDL help [message #93777 is a reply to message #93772] |
Fri, 14 October 2016 02:25  |
Markus Schmassmann
Messages: 129
Registered: April 2016
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Senior Member |
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On 10/14/2016 07:08 AM, Cheryl wrote:
> On Thursday, October 13, 2016 at 9:39:33 PM UTC-7, Cheryl wrote:
>> I am new to IDL world, and was wondering if you can help me create a loop.
>>
>> I need to create an array by replacing all values in 'a' that are greater than 5 by 20.
>>
>> c= where(a gt 5) then [c] = 20
>>
>> Is this the correct way to do it?
>>
>> Thanks
>
> I think i found a way to do it
>
> a[where(a gt 5,/null)]=20 is it correct?? How can I create an array for this?
> I tried to do :c= a[where(a gt 5,/null)]=20, but I keep getting a syntax error
if you want to retain a unchanged, then
b=a
b[where(b gt 5,/null)]=20
otherwise, just
a[where(a gt 5,/null)]=20
if a is already an array, so will b, and a remains an array
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| Re: Where.. Then Loop IDL help [message #93782 is a reply to message #93777] |
Fri, 14 October 2016 11:20 |
smnadoum
Messages: 24
Registered: June 2016
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Junior Member |
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On Friday, October 14, 2016 at 2:25:22 AM UTC-7, Markus Schmassmann wrote:
> On 10/14/2016 07:08 AM, Cheryl wrote:
>> On Thursday, October 13, 2016 at 9:39:33 PM UTC-7, Cheryl wrote:
>>> I am new to IDL world, and was wondering if you can help me create a loop.
>>>
>>> I need to create an array by replacing all values in 'a' that are greater than 5 by 20.
>>>
>>> c= where(a gt 5) then [c] = 20
>>>
>>> Is this the correct way to do it?
>>>
>>> Thanks
>>
>> I think i found a way to do it
>>
>> a[where(a gt 5,/null)]=20 is it correct?? How can I create an array for this?
>> I tried to do :c= a[where(a gt 5,/null)]=20, but I keep getting a syntax error
> if you want to retain a unchanged, then
>
> b=a
> b[where(b gt 5,/null)]=20
>
> otherwise, just
>
> a[where(a gt 5,/null)]=20
>
> if a is already an array, so will b, and a remains an array
Thanks so much.
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