comp.lang.idl-pvwave archive: archive » Fortran -> IDL translator

Home » Public Forums » archive » Fortran -> IDL translator

Show: Today's Messages :: Show Polls :: Message Navigator
E-mail to friend

Re: FORTRAN -> IDL [message #10723 is a reply to message #2702]

Sun, 11 January 1998 00:00

Kevin Ivory
Messages: 71
Registered: January 1997

Member

Kelly Dean wrote:
>
> I am converted some FORTRAN code into IDL, but I am confused what this
> FORTRAN statment "SINE(X)=SIN(.01745329*X) " in this function is trying
> to do.

It looks like it takes the angle in degrees X, calculates the sine
and puts it into the Xth array element of the array SINE.
Something like IDLs
sine = sin(!dtor * x)
where both x and sine are arrays.

Hope this helps
Kevin
--
Kevin Ivory Tel: +49 5556 979 434
Max-Planck-Institut fuer Aeronomie Fax: +49 5556 979 240
Max-Planck-Str. 2 mailto:Kevin.Ivory@linmpi.mpg.de
D-37191 Katlenburg-Lindau, GERMANY http://www.gwdg.de/~kivory2/

Report message to a moderator

[Message index]

		Fortran -> IDL translator By: uk2 on Wed, 31 August 1994 15:50
		Re: Fortran -> IDL translator By: amaravad on Fri, 02 September 1994 09:01
		Re: FORTRAN -> IDL By: Harald Frey on Mon, 12 January 1998 00:00
		Re: FORTRAN -> IDL By: Robert S. Hill on Sun, 11 January 1998 00:00
		Re: FORTRAN -> IDL By: rivers on Sun, 11 January 1998 00:00
		Re: FORTRAN -> IDL By: Kevin Ivory on Sun, 11 January 1998 00:00

Previous Topic:	IDL procedure to read UF data
Next Topic:	Problem setting up emacs idl-shell

-=] Back to Top [=-

[ Syndicate this forum (XML) ] [

] [

]

Current Time: Wed Oct 08 17:45:04 PDT 2025

Total time taken to generate the page: 0.00484 seconds