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Re: warning: (all(part1))(part2) = part2*0. [message #11971 is a reply to message #11882]

Fri, 05 June 1998 00:00

steinhh
Messages: 260
Registered: June 1994

Senior Member

R. Bauer wrote:

> (all(part1))(part2) = part2*0.

What you're doing here is to assign values to parts of a
temporary value, almost as if you're saying

5*all(part1) = 1

since (all(part1)) is a temporary value (actually, an rvalue)
like any other expression.

I think the error here is that IDL's compiler does not protest,
but instead generates code (seemingly) to do assignments to
a temporary value.

What you should do (with the intended (?) effect) is:

all(part1(part2)) = part2*0

Regards,

Stein Vidar

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[Message index]

		warning: (all(part1))(part2) = part2*0. By: R. Bauer on Thu, 04 June 1998 00:00
		Re: warning: (all(part1))(part2) = part2*0. By: R. Bauer on Fri, 05 June 1998 00:00
		Re: warning: (all(part1))(part2) = part2*0. By: steinhh on Fri, 05 June 1998 00:00

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